vòng tròn Ơle (in english)

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Người gửi: Điền Thị Ngọc Linh
Ngày gửi: 22h:12' 31-01-2010
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Số lượt tải: 8
Nguồn:
Người gửi: Điền Thị Ngọc Linh
Ngày gửi: 22h:12' 31-01-2010
Dung lượng: 564.0 KB
Số lượt tải: 8
Số lượt thích:
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THE NINE-POINT CIRCLE
The nine-point circle, discovered by Feurbach in about 1820, and has been attributed to several different people, including Brianchon and Poncelet, Terquem (who coined the term "nine-point circle“.
And it has been known as(apparently incorrectly, but still commonly done) Euler circle.
Containing the midpoints of the three sides of the triangle and the feet of the three altitudes. Its center is the midpoint of the segment joining the orthocenter and the circumcenter of the triangle
Proof
In triangle ABC, since D and E are midpoints of sides AB and AC (by construction), then segment DE is parallel to side BC.
In triangle BCH, since M and P are midpoints of sides BH and HC (by construction), then segment MP is parallel to side BC.
Since segment DE is parallel to side BC, and segment MP is parallel to side BC, then segments DE and MP are parallel to each other.
In triangle BAH, since M and D are midpoints of sides BH and BA (by construction), then segment MD is parallel to side HA.
In triangle CAH, since E and P are midpoints of sides AC and HC (by construction), then segment EP is parallel to side HA.
Since segment MD is parallel to side HA, and segment EP is parallel to side HA, then segments MD and EP are parallel to each other.
Since segment MD is parallel to segment HA, and segment HA lies on segment AL, then segment MD is parallel to segment AL.
Since segment AL is perpendicular to side BC by construction (AL is the altitude from point A to side BC), and side BC is parallel to segment DE, then segment AL is perpendicular to segment DE.
Since segment MD is parallel to segment AL, and segment AL is perpendicular to segment DE, then segment MD is perpendicular to segment DE.
Thus, we have that quadrilateral DEPM is a rectangle. Since the opposite angles of this quadrilateral are supplementary, it follows that the quadrilateral can be inscribed in a circle.
Similarly, quadrilateral DNPF is a rectangle, and it can be inscribed in a circle
Therefore, points D, N, E, P, F, and M are on a common circle, with one diameter of the circle being segment DP, since this segment is a diagonal of both rectangles. The center of this circle, then, is the midpoint of segment DP. Let this center be point O.
Now, since segment AL is an altitude, angle NLF is a right angle. But segment NF is also a diameter of our circle (it is a diagonal of rectangle DNPF), so it follows that point L must lie on this circle.
Similarly, points J and K are on the circle.
Therefore, all nine points D, E, F, J, K, L, M, N, and P lie on the same circle, called the nine-point circle. QED.
HERON’S FORMULA
where s is the semiperimeter of the triangle:
Heron`s formula can also be written as:
Proof
DID YOU KNOW ??? ^^…..
INTERCEPT THEOREM
THALES’ THEOREM
Thales` theorem states that if A, B and C are points on a circle where the line AC is a diameter of the circle, then the angle ABC is a right angle.
The nine-point circle, discovered by Feurbach in about 1820, and has been attributed to several different people, including Brianchon and Poncelet, Terquem (who coined the term "nine-point circle“.
And it has been known as(apparently incorrectly, but still commonly done) Euler circle.
Containing the midpoints of the three sides of the triangle and the feet of the three altitudes. Its center is the midpoint of the segment joining the orthocenter and the circumcenter of the triangle
Proof
In triangle ABC, since D and E are midpoints of sides AB and AC (by construction), then segment DE is parallel to side BC.
In triangle BCH, since M and P are midpoints of sides BH and HC (by construction), then segment MP is parallel to side BC.
Since segment DE is parallel to side BC, and segment MP is parallel to side BC, then segments DE and MP are parallel to each other.
In triangle BAH, since M and D are midpoints of sides BH and BA (by construction), then segment MD is parallel to side HA.
In triangle CAH, since E and P are midpoints of sides AC and HC (by construction), then segment EP is parallel to side HA.
Since segment MD is parallel to side HA, and segment EP is parallel to side HA, then segments MD and EP are parallel to each other.
Since segment MD is parallel to segment HA, and segment HA lies on segment AL, then segment MD is parallel to segment AL.
Since segment AL is perpendicular to side BC by construction (AL is the altitude from point A to side BC), and side BC is parallel to segment DE, then segment AL is perpendicular to segment DE.
Since segment MD is parallel to segment AL, and segment AL is perpendicular to segment DE, then segment MD is perpendicular to segment DE.
Thus, we have that quadrilateral DEPM is a rectangle. Since the opposite angles of this quadrilateral are supplementary, it follows that the quadrilateral can be inscribed in a circle.
Similarly, quadrilateral DNPF is a rectangle, and it can be inscribed in a circle
Therefore, points D, N, E, P, F, and M are on a common circle, with one diameter of the circle being segment DP, since this segment is a diagonal of both rectangles. The center of this circle, then, is the midpoint of segment DP. Let this center be point O.
Now, since segment AL is an altitude, angle NLF is a right angle. But segment NF is also a diameter of our circle (it is a diagonal of rectangle DNPF), so it follows that point L must lie on this circle.
Similarly, points J and K are on the circle.
Therefore, all nine points D, E, F, J, K, L, M, N, and P lie on the same circle, called the nine-point circle. QED.
HERON’S FORMULA
where s is the semiperimeter of the triangle:
Heron`s formula can also be written as:
Proof
DID YOU KNOW ??? ^^…..
INTERCEPT THEOREM
THALES’ THEOREM
Thales` theorem states that if A, B and C are points on a circle where the line AC is a diameter of the circle, then the angle ABC is a right angle.
 







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